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multiple values proposal

                                                                    Remember,
   CALL-WITH-CURRENT-CONTINUATION never creates a new continuation but rather
   simply reifies the one it was called with. 

But this certainly does not mean that
(call/cc (lambda (k1)
           (call/cc (lambda (k2)
                      (or (eq? k1 k2) (eqv? k1 k2)) )) ))
is true albeit similarly reified (not created) continuations are compared.

		Christian.