Student: leeying
Assignment: 2
Grader: Charlie

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Bresenham:

program runs, buggy (55):                   55
correct implementation of Bresenham (20):   20
no floats and divides (20):                 10
extra credit (5):                            2
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total (100):                                87

Cohen-Sutherland:

program runs, buggy (55):                   55
inside case correct (10):                   10
outside case correct (10):                   5
one clip correct (10):                      10
two clips correct (10):                     10
extra credit (5):                            0
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total (100):                                90


Comments:
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Bresenham:
You should not have used floats to compare the
slope. Comparing m to 1 is the same as comparing
dy to dx. So you could have gotten rid of all
the floats.

To have really simple code, you code have
implemented all 8 octants with 1 loop.

Cohen-Sutherland:
Good! One minor error though. There is a case
when a line should be external but your algorithm
returns clipped. This happens when the line is
not immediately trivially rejected.
For example, a line that has endpoints with
outcodes 0100 and 0001.


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